A New Definition

Calculus Level 1

∫ 0 ∞ e − x d x = ? \large \int_{0}^{\infty} e^{-x} \mathrm dx =?


The answer is 1.

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1 solution

∫ 0 ∞ e − x d x = − e − x ∣ 0 ∞ = − ( 0 − 1 ) = 1 \displaystyle \int_{0}^{\infty} e^{-x} \mathrm dx = \left . -e^{-x} \right|_{0}^{\infty} = -(0-1) = \boxed{1}

A new definition to 1. \text{ A new definition to 1.}

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