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Compute H ( 4 ) H(4) , where H ( n ) H(n) denotes the Hyperfactorial function.


The answer is 27648.

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2 solutions

Rishabh Jain
Mar 26, 2016

Hyperfactorial is defined as: H ( n ) = k = 1 n k k \LARGE H(n)=\prod_{k=1}^n k^k Putting n = 4 n=4 we get, H ( 4 ) = 1 1 2 2 3 3 4 4 \Large H(4)=1^1\cdot 2^2\cdot 3^3\cdot 4^4 = 2 10 27 = 27648 \Large =2^{10}\cdot 27=\huge\boxed{27648}

Swapnil Das
Mar 26, 2016

The hyperfactorial function is defined as H ( n ) = i = 1 n i i = 1 1 2 2 3 3 4 4 n n \large H(n) = \prod^{n}_{i = 1} i^i = 1^1 \cdot 2^2 \cdot 3^3 \cdot 4^4 \cdot \ldots \cdot n^n . Thus, H ( 4 ) = 27648 H(4) = 27648 .

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