Given a right-angled triangle which area is the same as the length of the hypotenuse, let its 2 shorter sides be x and y.
When x+y is at its minimum, calculate the area of the triangle.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let the triangle be ABC with the right angle at A, and P the foot of the perpendicular from A to BC. Then AP=2. Let BP=x. Then by similar triangles ABP and ACP, CP = x 4 . By AM-GM, the length of the hypotenuse, and hence the area, is x + x 4 ≥ 4 . Equality can be achieved in an isoceles right triangle.