A Nice Story

Algebra Level pending

A poet met a tortoise under a tree. When the tortoise was the poet's current age, the poet was one-fourth of his current age. When the tree was the tortoise's current age, the tortoise was one-seventh of its current age. If the sum of the ages of the poet, tree and tortoise is 264 years, find the age of the tree in years.

Note: Their age is the total number of years completed in their lifetime. The number of months and days can be omitted. For example, if one's age is 23 years, 4 months and 3 days, then consider their age as 23.


The answer is 143.

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1 solution

Let the ages of the poet, tortoise, and tree be x x , y y , and z z respectively.

When the poet was one-fourth his current age that is 1 4 x \frac 14 x , which was x 1 4 x x - \frac 14 x years ago, the tortoise, current age y ( x x 4 ) y - \left(x - \frac x4\right) was x x years old. In algebraic equation, we have:

y ( x x 4 ) = x y = x + x x 4 = 7 4 x \begin{aligned} y - \left(x - \frac x4 \right) & = x \\ \implies y & = x + x - \frac x4 = \frac 74x \end{aligned}

Similarly,

z ( y y 7 ) = y z = y + y y 7 = 13 7 y = 13 7 × 7 4 x = 13 4 x \begin{aligned} z - \left(y - \frac y7 \right) & = y \\ \implies z & = y + y - \frac y7 = \frac {13}7y = \frac {13}7 \times \frac 74 x = \frac {13}4x \end{aligned}

Then we have:

x + y + z = 264 x + 7 4 x + 13 4 x = 264 6 x = 264 x = 44 z = 13 4 × 44 = 143 \begin{aligned} x+y+z & = 264 \\ x + \frac 74 x + \frac {13}4x & = 264 \\ 6 x & = 264 \\ \implies x & = 44 \\ z & = \frac {13}4 \times 44 = \boxed{143} \end{aligned}

Sir, your solutions are beautifully illustrated.

Aryan Sanghi - 1 year, 3 months ago

Glad that you like it.

Chew-Seong Cheong - 1 year, 3 months ago

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