A Normal Problem!

Let the normal at the point $P$ to the hyperbola $\dfrac{(x-2)^2}{10} - \dfrac{(y+4)^2}{28} = 1$ meet the tranverse axis in $A$ and the conjugate axis in $B$ . A perpendicular $CF$ is drawn from the centre of the hyperbola to the normal. If $p=PA \times PF$ and $q = PF \times PB$ , find the value of $p+q$ .