A number theory problem by abhishek anand

Number Theory Level 3

A natural number k is such that k^ 2 < 2014 < (k + 1)^2 . What is the largest prime factor of k?


The answer is 11.

Abhishek Anand by abhishek anand , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

There is a typo in the question. It should be k^2 NOT k 2. 2014 = 44.8.... S o k = 44 a n d l a r g e r p r i m e m u m b e r 11. \sqrt{2014}=44.8....So~~~ k=44~and ~larger~prime~mumber~ \large 11 .\\~~\\
I think the level and points are high.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

sorry i did it by mistake thank you for pointing out i have edited the question

abhishek anand - 6 years, 2 months ago

yes the points seem to be too high

Ansh Bhatt - 6 years, 1 month ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...