Let x 1 , x 2 , … , x 2 0 1 4 be real numbers different from 1, such that x 1 + x 2 + ⋯ + x 2 0 1 4 = 1 and 1 − x 1 x 1 + 1 − x 2 x 2 + ⋯ + 1 − x 2 0 1 4 x 2 0 1 4 = 1 . Find the value of 1 − x 1 x 1 2 + 1 − x 2 x 2 2 + ⋯ + 1 − x 2 0 1 4 x 2 0 1 4 2 .
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An easy cute one Abhishek. let the sum given be s1 and s2 respectively.s2-s1 gives you the answer.