A number theory problem by Anandmay Patel

A number is divisible by 6 if and only if it is divisible by both 2 and 3 (it's prime factors).

As the divisibility rule regarding 3 is the divisibility of the sum of the digits of our number by 3 (and this is now 1+2+3+5+6+4=21), we cannot find such a rearrangement of the specified digits (as it won't change their sum) , which would result in a number which is divisible by 2 but not by 6 (as it will be always divisible by 3).

Therefore, n = 0, and by substituting this into the original equation we get:

$5x - 98 = 0 \\$

$x= \boxed {19.6}$