A number theory problem by Ankit Nigam

Number of divisors of the form 4n+2 (n \ge 0) of the integer 240 is _

PRACTICE FOR BITSAT HERE

8 9 3 4

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2 solutions

Edwin Gray
Dec 28, 2018

The factors are 2,6,10,30. Ed Gray

Akshay Sant
Apr 16, 2015

Hey Bro edit The Question You Have posted the answer too After is check it Out By The way Nice Problem... I Think Its previous IIT Problem Isnt it??

thanks for the observations.. I will change it soon

Ankit Nigam - 6 years, 1 month ago

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