A number theory problem by Arka Das

Number Theory Level pending

1+2+3+..........+99+!100 What is the value of the sum?


The answer is 5050.

Arka Das by Arka Das , 20, India

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1 solution

Anik Mandal
May 20, 2015

1 + 2 + 3 + . . . . . . . . . . + ( n − 1 ) + n = n ( n + 1 ) 2 \displaystyle 1+2+3+..........+(n-1)+n = \dfrac{n(n+1)}{2}

So \text {So} 1 + 2 + 3 + . . . . . . . . . . + 99 + 100 = 100 ( 100 + 1 ) 2 = 5050 \displaystyle 1+2+3+..........+99+100 = \dfrac{100(100+1)}{2} = 5050

1 Helpful 0 Interesting 0 Brilliant 0 Confused

@Arka Das How is my solution? And to learn about how to write Questions and Solution(by a language known as Latex) click here

Anik Mandal - 6 years ago

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