Find the largest palindrome number that is the product of two two-digit numbers.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
I didn't have a good mathematical formula for solving this, so I simply used the process of elimination. Starting with 9999, 9889, 9779, I worked my way back until I got to 9009. Since 99 is the largest 2-digit number, I started with 99 and worked back until the opposing factor exceeded two digits, then moved to the next lower palindromic number and started again. Eventually I reached 9009, which is the product of 91 and 99. If there's a formula out there for this, I would greatly appreciate it if someone would post it here.