A number theory problem by Gautam Arya

The equation 3 x + 5 y = 53 3x + 5y = 53 has exactly 4 pairs of positive integer solutions: ( x , y ) = ( 1 , 10 ) , ( 6 , 7 ) , ( 11 , 4 ) , ( 16 , 1 ) (x,y) = (1,10), (6,7), (11,4), (16,1) .

Find the largest possible value of k k such that the equation 3 x + 5 y = k 3x + 5y = k has exactly 4 pairs of positive integer solutions ( x , y ) (x,y) .


The answer is 75.

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1 solution

Giorgos K.
Feb 24, 2018

I just searched the first 1000 k on Mathematica

Select[Range@1000,Length@Solve[3x+5y==#&&x>0&&y>0,{x,y},Integers]==4&]

which returns all the k with exactly 4 pairs of positive integer solutions

{53, 56, 58, 59, 61, 62, 63, 64, 65, 66, 67, 69, 70, 72, 75}

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