An algebra problem by Hammad Shah

$14$ % students failed, so passed $86$ % students.

now, $86$ % is= $559$

or, $1$ % is = $\frac{559}{86}$

or, $100$ % is= $\frac{559 \times 100}{86}$ = $650$

so, the number of failed students are= $650-559$ = $91$

Let total number of students be N

Let number of students who passed be P and number of students who failed be F

So N = P + F

14% students failed => F = 0.14*N

559 students passed => P = 559

Thus, N = 0.14*N + 559

=> N - 0.14*N = 559

=> 0.86*N = 559

=> N = 650

=> F = 0.14*650 = 91

Hence, number of students who failed is 91

nice sol. Furia

559/.86 = 650 X .14 = 91 .

Total students = X
students failed =14X/100
students passed = 559
So.....14X/100 = X - 559
Therefore X = 650
650 - 559 = 91(Ans.)