Factoring into primes

a b c \overline{abc} is a three digit number, where a a is in the hundreds digit, b b is in the tens digit and c c is in the ones digit.

Let R ( a b c ) R = ( 2 a ) × ( 3 b ) × ( 5 c ) R(abc)R = (2^a)\times(3^b)\times(5^c) ; for example, R ( 140 ) R = ( 2 1 ) × ( 3 4 ) × ( 5 0 ) = 162 R(140)R=( 2^1)\times(3^4)\times(5^0)=162 .

For how many three digit numbers a b c \overline{abc} does the function R ( a b c ) R R(abc)R yield a prime number?

two one five four three

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1 solution

Hana Wehbi
Aug 2, 2017

There are three solutions here ( 100 ) , ( 010 ) , ( 001 ) (100),(010),(001) . Since we need the three digit number, so there is only one which is ( 100 ) (100) and the prime number will be 2 \boxed{2} .

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