To Bart Or Not To Bart

Train goes 65 miles per 1 hr or about 65 miles per 60 min , so it will take the train about 2.8 min to travel 3 miles, plus 5*3 = 15 min for the stops. Total time for the train is about 17.8 min .

$3 \text{ miles} \cdot \frac{60\text { min}}{65\text{ miles}} \approx 2.8\text{ min} \quad 15 + 2.8 = 17.8 \text{ min}$

Car travels at 10 miles per 1 hr or 10 miles per 60 min . It would take the car 18 min to travel 3 miles.

$3 \text{ miles} \cdot \frac{60 \text{ min}}{10 \text{ miles}} = 18 \text{ min}$

So the train is faster.

The distance to travel $(d)=3$ miles and speed of car $=10$ miles/hr while speed of train $=65$ miles/hr but train takes $5$ stops each for $3$ minutes. We know that Time $=\frac{\text{Distance}}{\text{Speed}}$ . Now ---

Time taken if gone by car $=(\frac{d}{10}) hr =\frac{3}{10}\text{ hr }=\frac{3\times 26}{10\times 26}= \boxed{\frac{78}{260}\text{ hr }}$

Time taken if gone by train $=(\frac{d}{65}) hr +(3\times 5)\text{ min } =(\frac{3}{65}+\frac{15}{60}) hr =\frac{3}{65}+\frac{1}{4} = \frac{12+65}{260}=\boxed{\frac{77}{260}\text{ hr }}$

We clearly can see that the train takes the least time out of the two modes of transport and so the answer is The train is faster.

Distance = 3 miles Speed of car = 10 miles per hour Speed of train = 65 miles per hour

Time taken by car = Distance/Speed of car =3/10 hours 1 hour = 60 mins 3/10 hours = 3/10 x 60

Time taken by car= 18 mins

Time Taken by Train = Distance/Speed of Train + Stop Time at each station = 3/65 hours +(3 x 5)minutes 1 hour =60 mins 3/65 hours = (3/65) x 60 mins

Time Taken by Train = 180/65 +15 mins

Hence train takes less time

$Time=\frac{Distance}{Speed}$ . The time taken to travel to work by car is: $Time=\frac{3m}{10mh^{-1}}(60minh^{-1})$ $Time=18min$

On the other hand, time taken to travel to work by train is: $Time=\frac{3m}{65mh^{-1}}(60minh^{-1})+15min$ $Time\approx 17.77min$

Therefore, the train is faster.

distance=speed*time'

car takes him to office in a time of t=(3/10)*60 minutes=18 min

train takes him to office in atime of t'=[(3/65) 60+5 3]minutes=17.76 min

so he chooses train to travel

the train runs 60 mile per hour....which mean it takes time for 3 mile is 2.72 minute+(3*5) minutes=17.72 minute for stop......but the car take 18 minute..so train is faster...

distance=3 miles Avg. speed of car =10 miles/hr time taken = distance/speed =3/10 hrs = 0.3 hrs avg speed of train =65 miles/ hr Stopping time =5*3 min=15 mins total time taken =distance/speed +stopping time =3/65 + 15/60(hours) =0.296 hrs therefore train is faster.!!!

Train and car go 3 miles. The train's velocity 65 miles per hour. So, it needs 3/65=0.046h =2.76m So, it needs total=(5*3)+2.76=17.76m

The car's velocity =10miles per hour So, it needs=3/10 hour =0.3hour =18min

infect train is more faster than the car it travels 60 divided by 65 i.e equal to 0.902 and person have to travel 3miles 3 0.902 equals to 2.7 5min to stops than 5 3=15 i.e 15+2.7=17.7 similar for car 60 /10 equals to 6and he have to travel 3 miles than 3*6=18min takes to travel by car

for car t=s/v=0.3hr=18min, for train t=s/v hr +5*3min=.046hr+15min=2.76min+15min=17.76min

speed of car is 10mile/hour so to travel 3 mile the car will take (3 60)/10=18min but the train will take (3 60)/65=2.79 min+5*3min of 5 stops }=17.79

Since t=d/s, t for the car should be 3mi/10 mi/h=0.3 h and t for the train should be 3 mi/65 mi/h=3/65 h + 15/60 h =0.197 hence, the train is faster

(I rounded most of my answers, factors etc.) 1) Car...10 miles divided by 3 = 3miles (distance) Now I do the same operation for the time 1 hour divided by 3 = 20 min. (Time it would take to go by car for 3 miles) 2) Train...65 miles divided by aprx. 20= 3 miles Now I do the same operation with the time 1 hour divided by aprx. 20 = 3 min. 3)Compare....3 miles/20 min. of car vs 3 miles/18 minutes of train ( Although the train stops only every 13 minutes and the person would have already gotten off before then, if we add the 15 minutes taken in total of all the stops, the 3/18 still beats 3/20) Therefore the train is faster.

Train goes 65 miles per 1 hr or about 65 miles per 60 min,and Stops, 5x3 = 15 min for the stops so it will take 0.9333 min for one mile and about 2.8 min to travel 3 miles and 15 min of stop Total time for the train is about 17.8 min.

Car travels at 10 miles per 1 hr or 6 min for 1 mile and car would take the car 18 min to travel 3 miles.

So the train is faster.

train travels in 3miles 60min/65miles=2.77 5 3+2.77=17.77min and car travels in 3miles*60min/10miles=18min, so the train is faster

car: t = v/d = 3/10 = 0.3 hr x 60 mins = 18 mins

train: t = v/d = 3/65 = 0.046 hr x 60 mins = 2.76 mins + (3 mins stop x 5 stops) = 17.76 mins

train is faster.

as the speed of the car = 10miles/h(60 min) so it takes 6 minutes to cover one mile ,so it takes 18 minutes to cover 3 miles and as the train has speed 65 miles / h so it takes 0.923 minutes to cover one mile and take 2.769 minutes to cover 3 miles and since it has to stop 5 times for 3 minutes(15 minutes) so it take 17.9 minutes and because of that the train is faster

let d be the distance(3 Mile), t1 be the time needed for train and t2 be the time needed for car, u1 be the speed of train and u2 ,speed of car

for train, T1 = t1 + (15/60) hours where t1 = d / u1 so, T1 = 0.29 hour for Car , T2 = d/u2

so T2 = 0.3 hour as T1<T2. ans is T1

In Calculation Train is faster , but in Actually Car is faster because Distant from Station to Home Asn Similarly station to Office And purcahsing Of tickets wait for Train .then Car is Home To Office directly . There Is Time Saving to Go in car

V(speed) =d(distance) /t(time) t=d/v Vcar =10m/h. Vtrain=65m/h. d=3 miles t(car) =3/10=0.3 hour t(train) =3/65=0.04615 hour + 0.25 =0.029615 hour.. Which is less than the time the car takes the0.25 hour we added to the train time is the. Time the train takes in stations.. (3 5=15 minutes) = 0.25 hour..