A number theory problem by Keshav Bassi
A perfect square can be expressed in the form of the four digit integer, where and are natural numbers. Find that number.
The answer is 7744.
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1 solution
aabb=1000a+100a+10b+b=1100a+110b=11(100a+b). 11(100a+b)=x^2 so 100a+b=11×n^2 since 100a+b is from the form a0b the only option that setisfis this is n=8. so 100a+b=704 a=7 b=4