find the number which when devided by 2,3,4,5,6,7,8,9,10 the remainder is 1,2,3,4,5,6,7,8,9 respectively ?
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first of all lets find a number which completly devided by 2,3,4,5,6,7,8,9,10 obesely it will be LCM of these numbers. LCM=2520 now if we substract 1 from this number we will get remainder less than 1 from devider answer=2520-1=2519