A number theory problem by Madhavarapu Revanth
Number Theory
Level
2
A six digit number is formed by repeating a three digit number twice (like 123123). Such numbers are always divisible by which of the following numbers?
25
101
1001
111
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1 solution
This number is the result of a multiplication of 123 times 7, 11 and 13. 7 times 11 times 13 equals 1001, so 123 x 1001 = 123123 / 123 = 1001