find the smallest integer k such that the product of 420 and k is a perfect square.
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420 = 2^2 * 3 * 5 * 7 (prime factors)
That means, if we multiply 420 by 3 * 5 * 7 = 105, then 420*105 becomes a perfect square because
420 * 105 = 2^2 * 3^2 * 5^2 * 7^2