A function is defined as f ( x , y ) = 2 3 × 3 4 x + 5 5 9 0 y + 5 8 8 .
Given that ∃ x , y ∈ Z + : f ( x , y ) ≡ 0 ( m o d 4 3 ) .
If f ( x , y ) ≡ N ( m o d 5 5 9 ) . Then what is the value of N . If you get multiple values of N , then submit the answer as the sum of all the values N .
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This is same, how I did.
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Did you check for the other possible values of x ? Is it true that the result holds for all values of x satisfying the congruence modulo 4 3 ?
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I checked for quite few values ... then looked for its' multiples and came out with the result that x = 4 2 k + 2 ∀ k ∈ Z ≥ 0 .
And f ( x , y ) ≡ 0 , 3 4 4 ( m o d 5 5 9 ) ∀ x , y ∈ Z + .
@Alak Bhattacharya [Check this out.](https://brilliant.org/problems/5-card-combintions-watch-out/?ref_id=1585091)
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What is the connection between this question and that I didn't get.
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No connection, It is a fun question... It feels satisfying after finding the answer.
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5 5 9 0 y + 5 5 9 ≡ 0 ( m o d 4 3 ) for all integer y . So we have to find some positive integer x for which 2 3 × 3 4 x + 2 9 ≡ 0 ( m o d 4 3 ) holds. By direct inspection we see that x = 2 is a candidate for this. For x = 2 , 2 3 × 3 4 x + 2 9 = 2 6 6 1 7 ≡ 3 4 4 ( m o d 5 5 9 ) .