An algebra problem by Rohan Aggrawal

Algebra Level pending

What is the value of { (12+10) }^{ 2 }


The answer is 484.

Rohan Aggrawal by Rohan Aggrawal , 27, India

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4 solutions

Kyle Chui
Dec 22, 2014

(12+10)^2 = 22^2 = (22-2)(22+2)+2^2=20*24+4=480+4=484

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Rishabh Jain
Nov 17, 2014

oh!! really typical problem !!!

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Muhammad Sofyan
Sep 23, 2014

a^2=(a-b)(a+b)+b^2 (12+10)^2=(22-2)(22+2)+2^2 =20*24+4=480+4=484

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Rohan Aggrawal
Sep 22, 2014

it is in the form of (a+b)(a+b). so 12x12 + 10x10 + 2(12)(10). it is equal to 484.

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