A number theory problem by Varun Bansal

Find the missing number?

195
383
575
763
955
?


The answer is 1143.

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4 solutions

Fletcher Mattox
Mar 27, 2021

Um, why can't the answer be, say, 1175?

If f ( x ) = 1 3 ( 2 x 4 24 x 3 + 100 x 2 402 x + 105 ) f ( 1 ) = 195 , f ( 2 ) = 383 , f ( 3 ) = 575 , f ( 4 ) = 763 , f ( 5 ) = 955 , f ( 6 ) = 1175 f(x) = \frac{1}{3}(2x^4 - 24x^3 + 100x^2 - 402x + 105) \implies f(1)=195, f(2)=383,f(3)=575,f(4)=763,f(5)=955,f(6)=1175

Or for that matter, any of an infinite number of other answers, depending on which polynomial you pick.

Rahul Dhadve
Jul 9, 2014

as the number pattern shows: 1st digit from left side is odd and in ascending order=11 10th place is descending order=4 ones place is aternate of 5 and 3 so next number =3

Here is the pattern:

aₙ=aₙ₋₁+188((n-1) mod 2)+192(n mod 2)

if a₁=195, a₂=383, ...

a₆=955+188 (5mod2)+192 (6mod2)=1143

Jitendra Kumar
Aug 1, 2014

There is a pattern in in even and odd numbers. 1st digit from left is increasing by 4 (from n-2) and middle digit is decreasing by 2(from n-2) and last digit is constant (same as n-2). Hence 1143 will be the solution.

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