A number when divided........

A number when divided by a divisor leaves a remainder of 5 and when divided by twice the divisor leaves a remainder of 45. Find the divisor?

All of the above 10 20 40

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1 solution

Andrea Palma
May 10, 2015

Write

n = q d + 5 n = q\cdot d + 5 n = q 2 d + 45 n = q^\prime \cdot 2d + 45

subtract the equations and get

( q 2 q ) d = 40 (q - 2q^\prime)d = 40

So the divisor d d is a divisor of 40 40 . Since 45 45 is a remainder of the division by 2 d 2d we have necessarily 45 < 2 d 45 < 2d . This inequality is true for only one divisor d d of 40 40 , namely d = 40 d = 40 .

n = 125 n = 125 and d = 40 d = 40 suit the assumptions.

Andrea Palma - 6 years, 1 month ago

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