A Perfect Factorial Number (Problem 1)
Prove that is equivalent to sum of its factors, is equivalent to , and the sum of 's factors is equivalent to .
If you don't understand, check out the discussion explaining this and comment down in the solutions section if you now understand: A Perfect Factorial Number
Note: Think of as a perfect number (i.e. the sum of its factors excluding itself.)
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1 solution
6 = 3 + 2 + 1 = 5 + 1 = 6 - Proves that 6 is equivalent to the sum of its factors
6 = 3 ! = 3 ∗ 2 ∗ 1 = 6 ∗ 1 = 6 - Proves that 6 is equivalent to 3 !
3 + 2 + 1 = 3 !
3 + 2 + 1 = 3 ∗ 2 ∗ 1
5 + 1 = 6 ∗ 1
6 + 6 = 1 2 = 6 - Proves that the sum of 6 's factors is equivalent to 3 !
Therefore the answer is Yes.