A Perfect Question!

The divisors of $6$ , lower than $6$ itself are $3$ . Namely $1, 2$ and $3$ . Summing these divisors we have $1+2+3 = 6$ so, by definition, $6$ is a perfect number . :) Enjoy!

All positive divisors of $6$ that is lower than $6$ is $1, 2,$ and $3$ . $1 + 2 + 3 = 6$ . So $6$ is a perfect number. (You can also use the formula "If $2^{p-1}$ is prime, $2^{p-1}(2^{p}-1)$ is perfect." Since $6 = 2^{2-1}(2^{2}-1)$ , $6$ is a perfect number.

$6= (2^{2-1})(2^2 -1)$ So it is perfect