Regular Polygons are arranged around a unit equilateral triangle as shown in the figure above.
If the hatched area can be written as d 1 3 d ( c + c ) + c − 1 a − b for square-free integers a , b , c and d . Find a + b + c + d .
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@Digvijay Singh and @ahmad saad do you think this problem is over rated? If one knows the value of sin 1 8 then he/she can solve the question easily.
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Yes, It wasn't a hard nut to crack. Just simple trigonomerty and geometry.
It must've been rated Level 4.
Edit: It is rated Level 4 now.
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I had solved it differently so I didn't get it in that exact form you wanted, so I couldn't answer the question as an integer. Maybe allow the actual area (rounded to some decimals) as an answer to allow for different solutions.
I essentially treated AB as the x axis. line AD would be y=tan(18)x and BC is y=-tan(60)x +root3.
the height of the intersection of those 2 lines is the height of the triangle. from which I get area. maybe a bit primitive but it works.. i think.
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