A Polynomial and a Triangle

Geometry Level 3

Let f ( x ) = x 3 4 x 2 + a x + b f(x) = x^3-4x^2+ax+b be a polynomial with 3 3 positive roots.
A triangle with side lengths equal to the roots of f ( x ) f(x) has an area of 1. 1.

Find f ( 2 ) f(2) .


The answer is 0.5.

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1 solution

Daniel Lee
Jul 4, 2017

Note that the sum of the roots is 4.

Now, if the roots are a, b, and c, then the area of the triangle is ( a + b + c 2 ) ( a + b + c 2 a ) ( a + b + c 2 b ) ( a + b + c 2 c ) \sqrt{ (\frac{a+b+c}{2})(\frac{a+b+c}{2}-a)(\frac{a+b+c}{2}-b)(\frac{a+b+c}{2}-c) } by Heron's formula.

But we realize that since f ( x ) f(x) factors into ( x a ) ( x b ) ( x c ) (x-a)(x-b)(x-c) , the area is just ( a + b + c 2 ) f ( a + b + c 2 ) \sqrt{ (\frac{a+b+c}{2})f(\frac{a+b+c}{2}}) !

Thus ( 2 ) f ( 2 ) = 1 f ( 2 ) = . 5 \sqrt{(2)f(2)}=1\rightarrow f(2)=.5 .

OH GOD I EXPANDED EVERYTHING AND USED VIETA'S RELATIONS STUPIDLY

Shourya Pandey - 3 years, 11 months ago

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