A calculus problem by Abdulrahman El Shafei

Calculus Level 4

lim x 0 x 1 + 1 x 2 = ? \large \lim_{ x\to0 } x\sqrt { 1+\frac { 1 }{ { x }^{ 2 } } } = \ ?

-1 The limit doesn't exist 1

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1 solution

Tom Engelsman
Dec 5, 2016

The above expression can be rewritten as:

x 1 + 1 x 2 = x x 2 + 1 x x \cdot \sqrt{ 1 + \frac{1}{x^2}} = x \cdot \frac{\sqrt{x^2 + 1}}{|x|}

of which division by zero is not permissible as x 0 x \rightarrow 0 in this case. Thus the limit doesn't exist.

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