What is the sum of the factors of the prime number 982 451 653?
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982451653 is a prime number. So it has only two divisors (1 and itself).
The sum is 1 + 9 8 2 4 5 1 6 5 3 = 9 8 2 4 5 1 6 5 4
Given that 9 8 2 4 5 1 6 5 3 is a prime number it has only two factors 1 and 9 8 2 4 5 1 6 5 3 and their sum is 9 8 2 4 5 1 6 5 3 + 1 = 9 8 2 4 5 1 6 5 4
@A W Make this problem harder by not giving that 9 8 2 4 5 1 6 5 3 is a prime number.
Since 9 8 2 4 5 1 6 5 3 is a prime number , the factors are 1 and 9 8 2 4 5 1 6 5 3 only. So the sum of the factors is 9 8 2 4 5 1 6 5 3 + 1 = 9 8 2 4 5 1 6 5 4
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By definition, a prime number has only two factors: 1 and itself. Since it is given that 9 8 2 4 5 1 6 5 3 is prime, then the sum of its factors is 9 8 2 4 5 1 6 5 3 + 1 = 9 8 2 4 5 1 6 5 4 .