A probability problem by Abhilash Yadav

In an annual state tournament 5 cricket teams participate. The champion team is chosen for this tournament by the usual elimination scheme. That is, the 5 teams are divided into pairs, and the 2 teams of each pair play against each other. The loser of each pair is eliminated, and the remaining teams are paired up again, etc. How many games must be played to determine the champion?


The answer is 4.

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1 solution

consider teams named A B C D and E respectively. Assume that A and B play and C and D play. E will be left out for this round. Say A and D win their respective matches. A and E now play while D is left out. Say E wins. Now the final is between E and D. This sums up to 4 matches ( A and B, C and D, A and E, D and E)

Live long and prosper, Stronak the Vuclan

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