Find the fundamental period of the function .
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The period of s i n x is 2 π , and the period of s i n ( n x ) is equal to n 2 π .This is because when you plot the graph of s i n x we can see that at 2 π the graph repeats.
Now when we double the value of x the graph repeats at p i like this ,
This can be generalized as the period of s i n ( n π ) is equal to n 2 π . Applying it in the question we get the period of s i n ( 3 6 x ) as 3 6 2 π = 1 8 π .And this can be checked by plotting the graph.