A geometry problem by Abhishek Kanigiri

Geometry Level 1

Find the fundamental period of the function f ( x ) = sin ( 36 x ) f(x) =\sin(36x) .

π 18 \frac\pi{18} π 36 \frac\pi{36} 72 π 72\pi 2 π 2\pi

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1 solution

The period of s i n x sinx is 2 π 2\pi , and the period of s i n ( n x ) sin(nx) is equal to 2 π n \frac{2\pi}{n} .This is because when you plot the graph of s i n x sinx we can see that at 2 π 2\pi the graph repeats.

Now when we double the value of x x the graph repeats at p i pi like this ,

This can be generalized as the period of s i n ( n π ) sin(n\pi) is equal to 2 π n \frac{2\pi}{n} . Applying it in the question we get the period of s i n ( 36 x ) sin(36x) as 2 π 36 = π 18 \frac{2\pi}{36} = \frac{\pi}{18} .And this can be checked by plotting the graph.

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