In shuffling a pack of playing cards, four cards were accidentally dropped. Find the probability that the missing cards should be one from each suit.
Give your answer to 3 decimal places.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The first card could be any of the 52 cards.
The second can only be one of the 39 in the remaining 3 suits.
The third card can only be one of the 26 in the remaining 2 suits.
The fourth card can only be one of the 13 in the only remaining suit.
The number of cards we have to choose from is decreasing by 1 with every card we pick, so we have the answer:
5 2 5 2 × 5 1 3 9 × 5 0 2 6 × 4 9 1 3 = 0 . 1 0 5 to 3 decimal places.