AN ELECTRON IS PLACED IN ONE OF THE CORNERS OF A CUBE SIDE 2cm.CALCULATE THE FLUX THROUGH ALL THE FACES IF THE ELECTRIC PERMITTIVITY IS E
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By Gauss law, Electric flux= Charge contained in the guassian surface / Electric permittivity
Here it is stated that an electron is placed at one of the corners. So that 1/8 of an electron is inside the gaussian surface. Therefore the charge of the electron inside the gaussian surface becomes 1/8e.
Final answer= (1/8e)/ E