A tuba gatherer went to the top of a coconut tree at an average speed of 1 fps and stay at the top to gather tuba for 1.5 minutes and then goes down at 2 fps. If the ellapsed time is 2 minutes, how high is the coconut tree(in feet)?
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Let T= total time covered and h= height of the tree
Then, T=t1 + t2 + t3
2(60) = h/1 + 1.5(60) + h/2
120 = h +90 +0.50h
h= 20 feet