A logic problem by Ansh Agrawal

Logic Level 2

If You have 9 balls and have weighing scale and if 1 of the ball is heavier then all other and the other have same weight so what is minimum number of steps you can find the heavier ball?

6 2 9 4 7

Ansh Agrawal by Ansh Agrawal , 20, India

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2 solutions

Ratul Pan
Apr 5, 2016

First divide the nine balls into s e t o f 3 set~ of~ 3 containing 3 b a l l s e a c h 3~ balls~ each i.e. s e t − A , s e t − B , s e t − C set-A~,~set-B~,~set-C

Then put any s e t − A , s e t − B set-A~,~set-B on the two sides of the weighing machine.

C A S E : I CASE:I

If the heavier ball lies in any of the two sets, it can be identified.

Then pick any two balls from that set and put them on the either sides of the weighing machine.

If they weigh same then the 3 r d 3^{rd} ball is the heavier one .

C A S E : I I CASE:II

If the two sets weigh same then repeat the rest of process from C A S E : I CASE:I .

Hence, 2 w e i g h i n g s 2~ weighings are to be done.

It was pretty easy and a repeated question. :))

4 Helpful 0 Interesting 0 Brilliant 1 Confused

Ya But is interesting one @Ratul Pan

Ansh Agrawal - 5 years, 2 months ago
Andreas Wendler
Apr 4, 2016

  1. Weigh with 3 balls on each side. So you can determine which set of 3 balls contains the heavier one.

  2. Split the set with the heavier ball into 3 single balls whereat you weigh with 1 ball on each side. The heavier ball now can be measured unique.

2 Helpful 0 Interesting 0 Brilliant 0 Confused

Solid Answer @Andreas Wendler

Ansh Agrawal - 5 years, 2 months ago

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