A problem by Anuradha Dey
Level
pending
In a party, there one man dances exactly with 3 ladies & 1 woman dances exactly with 3 men . there are exactly two pairs are common with every men. how many people are there in party?
The answer is 8.
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1 solution
Men -- M1, M2... etc Women -- W1, W2.. etc
the pair can we arranged this way --
M1-W1; M1-W2; M1W3 -- FIRST PAIR
Now, we have a condition -- each men has exactly 2 women in common. so, we need 1 extra woman for next pair
M2-W1; M2-W2; M2W4 LIKEWISE, WE CAN ARRANGE MEN FOR W4 AS WELL.
M3-W1; M3-W3; M3W4 Last Pair; -- M4-W2; M4-W3; M4-W4 TOTAL --
4 Men -- M1 M2 M3 M4 4 Women -- W1 W2 W3 W4 = 8
Answer is 8