An algebra problem by Aparna Ram

$2^n-2^{n-1}=$

$2 \cdot 2^{n-1}-2^{n-1}=$

$2^{n-1}(2-1)=$

$2^{n-1}$

The first one is twice the value of the second one. This is only true because the first index is a number that is the next to the second index.

So, 2^4 - 2^3 = 16 - 8 = 8

And 8 = 2^3

Just like: 2^2 - 2^1 = 4 - 2 = 2

And 2 = 2^1

Sorry for any mistakes in the explanation, still learning English.

write given as 2^2013(2^1-1) which is equal to 2^2013