Trigonometry

Geometry Level 1

cos 1 cos 2 cos 3 cos 201 6 = ? \large \cos1^\circ \cos2^\circ \cos3^\circ \cdots \cos2016^\circ =\, ?

2016 -2016 -1 0 1

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3 solutions

Hana Wehbi
Jul 10, 2016

We are taking the product of c o s 1 × c o s 2 × c o s 3.... × c o s 2016 cos 1\times cos2\times cos 3....\times cos 2016 . We know that there is some value whose c o s = 0 cos =0 \implies , the product=0. ( for example c o s 90 = 0 cos 90=0 )

Ashish Menon
Jul 13, 2016

cos 90 ° \cos{90}^° comes in between which is 0 0 making the entire product 0 \color{#3D99F6}{\boxed{0}} .

Viki Zeta
Jul 11, 2016

c o s 1 × c o s 2 × c o s 3 × . . . × c o s 2016 = c o s 1 × c o s 2 × . . . × c o s 90 × . . . × c o s 2016 = c o s 1 × c o s 2 × . . . × 0 × . . . × c o s 2016 = 0 cos1\times cos2\times cos3\times...\times cos2016=cos1\times cos2\times...\times cos90\times...\times cos2016 = cos1\times cos2\times ... \times 0 \times ... \times cos2016 = 0

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