There is one odd integer N between 400 and 600 that is divisible by both 5 and 11. Find the sum of the digits of N.
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i found 495 but didnt add the digits
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Dude, Thats bad coz the first thing you do when you solve a question is that you READ it CAREFULLY
1 1 × 5 = 5 5 .it is both odd and divisible by 5 and 11.
so, the answer will be= 4 4 0 + 5 5 = 4 9 5
There are Three Numbers Between 400 and 600 that are divisible by 5 and 11 . These are 440 , 495 and 550 and the sum of digits are 8 , 18 and 10 respectively. Only 495 is odd so answer is 18
An odd multiple of five must end with the digit five. In a three digit multiple of eleven the first digit and the last digit must add up to the center digit. 5 + 5 = 10, so there cannot be a possible value in between 500 and 600, so the first digit must be 4, 5 +4 = 9, so the number must be 495, 4 +5+9 = 18
well what I did...took 500/(5x11) and quotient was 9 therefore 9*55=495 4+9+5+18
Divisible by both 5 and 11 so multiples of 55 between 400 and 600 are 495 or 565 so the sum can be 16 or 18
565 is not a multiple of 55
565 is not a multiple of 11. 565/11=51.3636...
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It must be divisible by LCM(5,11)=55. Hence the odd multiple of 55 will be 495. So the answer is 4+9+5= 1 8