A problem by catherine almira
Level
pending
How many term of the geometric series, 4+6+9+... must be taken to obtain a sum exceeding 3000?
The answer is 15.
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1 solution
n = 0 ∑ 1 4 ( 4 × 1 . 5 n ) > 3 0 0 0 0-14 = 15 numbers