A geometry problem by Dhruv Ramdev

AED is 90 and BED is 40.

That means that AEB is 50 (AED - BED = 90 - 40 = 50).

The measure of BEC is AEC - AEB = 75 - 50 = 25

$75^\circ+40^\circ-90^\circ=25^\circ$

Given that AEC is 75

then CED must be 90-75=15

Thus BEC must be 40-15=25

90- (AEB+CED)= 90-65=25

x+y+z=90; x+y=75; y+z=40. Solving the system, have y=25.

From right angle AED ,by subtraqctingBED 40 degree,we get angle AEB = 50 degree. Subtracting from 75 degree we get angle BEC + 25 degree Ans. K.K.GARG,India

AEB=AED-BED=90-40=50; BEC=AEC-AEB=75-50=25...

90-AEB-CED= 90-50-15

Given that AEC is 75 then CED must be 90-75=15 Thus BEC must be 40-15=25

Given that AEC is 75 then CED must be 90-75=15 Thus BEC must be 40-15=25

AEC=75,AEB=50,then THE ANSWER is 75-50=25

40 + 75=115 - 90=25