If is a prime number greater than 2, then find the remainder when is divided by 2.
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First, you have to understand that you must ignore all evens,even if p is one, since even^b = even, no matter what as long as b is an integer. As we know, all primes are intergers. Also, if c is an odd interger, odd^c = odd. You must also understand that no matter what odd you choose, it will always get cancelled out by 1 since odd + odd(including 1) = even. I am also lazy,but I will show an example, so I used 3. 2mod(side note, I forgot how to use mods, all I know is they give remainders)(1^3 + 3^3) = 0.