A 17-kg ladder has a center of mass at G. If the coefficients of friction at A and B are m= 0.3 and n = 0.2, respectively, determine the smallest horizontal force that the man must exert of the ladder at point C in order to push the ladder forward.
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Apply the frictional forces at points A and B, the normal reactions at A and B. Write the conditions of equilibirium.
But take the moments about the centre of gravity of ladder, you will get afterwards the required force P.