A number theory problem by Gajender Singh

How many no. of factors does 2400 have?


The answer is 36.

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1 solution

Simrat Singh
Oct 24, 2014

P = A N × L M . . . . . . S O N O . O F F A C T O R = [ N + 1 ] [ M + 1 ] . . . . . . . . . . I F P = 2400 T H E N 2400 = 2 5 × 3 1 × 5 2 S O N O . O F F A C T O R = [ 5 + 1 ] [ 1 + 1 ] [ 2 + 1 ] = 6 2 3 = 36 P={ A }^{ N }\times { L }^{ M }......\infty \\ SO\quad NO.\quad OF\quad FACTOR=\left[ N+1 \right] \left[ M+1 \right] ..........\infty \\ IF\quad P=2400\\ THEN\quad 2400={ 2 }^{ 5 }\times { 3 }^{ 1 }\times { 5 }^{ 2 }\quad \\ SO\quad NO.\quad OF\quad FACTOR=[5+1][1+1][2+1]\\ =6*2*3=\bigstar 36\bigstar

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