i) A and C= p
ii)B and D = q
Find p+q
All the resistance is equal to 1
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Since from any corner , circuit is symmetric. Hence i/3 current flows in each branch. Apply Kirchhoff law in triangle ABC. we get 2i/3=i*R where R is net resistance b/w A and C. Again, Circuit is symmetric hence resistance b/w b and d is equal to resistance between a and c. Hence, net resistance is 4/3