A problem by gurvi sinha

Level pending

Of the 120 people in the room, 3/5 are women. If 2/3 of the people are married, what is the maximum no. of women in the room who could be unmarried?

15 30 40 20

Gurvi Sinha by gurvi sinha , 25, India

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2 solutions

Chris John
Feb 1, 2014

There are 72 women, 48 men. 80 people are married, so if all (a maximum) the men are married, there must be (a minimum of) 32 married women. This leaves (a maximum) 40 unmarried women

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i did this just using V e n n ′ s Venn's D i a g r a m Diagram

Rishabh Jain - 7 years ago
Yash Bansal
Jan 31, 2014

3/5 are women so 3/5 of 120=72 then no. of male =120-72 =48 as married person is 2/3 =2*120/3=80 for max no. of female to be unmarried, the all male should be married i.e 48 males are married, married female=80-48=32, so unmarried female =72-32=40

1 Helpful 0 Interesting 0 Brilliant 0 Confused

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