A problem by Hamdy El Shehabyy
Level
pending
If Abc is an obtuse angel triangle at B,sin c=3/5,then find sin(A+b+2c)
3/5
1
1/2
-3/5
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1 solution
Sin(A+b+2c)=sin(A+b+c+c)=sin(180+c)=-3/5