An algebra problem by hritik raj

Algebra Level 2

A dog takes 4 leaps for every 5 leaps of a hare but 3 leaps of a dog are equal to 4 of the hare ... compare their speeds

B)16:15 A) 16:5 D)15:1 C)9:4

1 solution

Chew-Seong Cheong
Sep 11, 2014

For the same time $t$ , dog moves $4 l_{dog}$ , while hare moves $5 l_{hare}$ . And $3 l_{dog} = 4 l_{hare} \Rightarrow l_{dog} = \frac {4}{3} [_{hare}$

Now, $\dfrac {v_{dog}}{v_{hare}} = \dfrac {4 l_{dog} }{ 5 l_{hare} } = \dfrac {4 \times \frac{4}{3} l_{hare} }{ 5 l_{hare} } = \dfrac {16 }{ 15 } = \boxed {16:15}$

An algebra problem by hritik raj

1 solution

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