A problem by Jaden Freebar
Level
pending
MATH X 4= HTAM What does F equal?
6
2
4
1
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1 solution
Anything times 4 is even, so we know that the last digit (M) is even. M must be 0, 2, 4, 6, or 8. If M is the first digit of a four digit factor and multiplying it by 4 doesn't create a 5 digit product, then M must be a low number: Either 0 or 2. If M is 0, H times 4 will equal 0, making H=0. that is impossible, so M=2. We know that M=2, so M times 4=H. That means H=8. so now we have 2AT8 X4= 8TA2. We carry 3 into the tens column because 4 X 8=32. A must be odd because 4G+1 must be odd. Since the 2 in the thousands of the factor becomes an 8 in the thousands of the product, that means there is no "carry" into the thousands. So that means that 4A + (carry into the hundreds) < 10. That means A is 0, 1 or 2. Combine this with the fact F is odd and so F must be 0. now we have 21T8 X 4= 8T12. We have 21T8 x 4 = 8T12. So 4T + 3 ends in a 1. This would make G either 2 or 7. So is 2128 x 4 = 8212? No. Therefore G must be a 7 Check: 2178 x 4 = 8712. Yes.