If the length of the hypotenuse of the right triangle equals the side length of the square, find the area of the yellow region .
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Let A be the hypotenuse of the white triangle.
Then A = 1 0 2 + 1 0 2 ≅ 1 4 . 1 4 .
But A = B , which is the side of the square, so the area of the square is 1 4 . 1 4 2 ≅ 2 0 0 .
The area of the triangle is simply 2 1 0 × 1 0 .
So finally, the yellow area is 2 0 0 − 5 0 = 1 5 0 .
Edited for formatting purposes
Using Pythagoras X = 1 0 2 + 1 0 2 = 2 0 0 = 1 0 2
The area of the square is X 2 = 2 0 0
The area of the triangle is 2 1 × b × h = 2 1 × 1 0 × 1 0
Hence the yellow area is 2 0 0 − 5 0 = 1 5 0
Relevant wiki: Pythagorean Theorem
Area of triangle=(1/2)bh=(1/2) * 10 * 10=50 square units
x=sqrt(10^2+10^2) using Pythagoras theorem
x=sqrt(200)
Area of square=x*x =sqrt(200) * sqrt(200) =200 square units
Therefore the area of yellow region =Area of square - Area of triangle = 200-50=150 square units
Area of squar = X^2 = 200 ------------------(1) Area of trangle = 1/2 × 10 ×10 = 50 -------(2) Area of yellow region = 200 - 50 = 150
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